Let be the quadratic variation and stop at . Its continuity and monotonicity imply and whenever . The standard martingale isometry after stopping by bounded quadratic variation gives ; in particular the stopped local martingale is square-integrable. This criterion follows by localization and the Doob L2 maximal inequality, which bound the second moment of the stopped supremum by and then permit removal of localization.
On one has , so the original and stopped paths agree through time . Therefore the Doob L2 maximal inequality and the Markov inequality giveThus
Take the stopping timesContinuity gives , with no overshoot at the first crossing. Stopping preserves the local martingale property, and the bounded case proved in question 4(i) makes each a continuous true martingale.
Every continuous path is bounded on each compact time interval, so almost surely. Hence this is also a localizing sequence consisting of bounded stopped martingales.
For the dyadic power variation of a continuous local martingale, write , and . Uniform continuity on gives almost surely, while the deterministic-partition characterization of quadratic variation gives in probability. In particular is bounded in probability.
If , then , and a factor tending to zero in probability times a sequence bounded in probability tends to zero in probability. ThusIf , the reverse comparison is . The assumed finite makes eventually bounded almost surely, so almost surely. By uniqueness of a limit in probability, almost surely. Its monotonicity gives for .
To finish without assuming any integrability of , apply the bound from part (i) to both and , with , and then let . For each the probability of a positive or negative excursion beyond is zero. Taking countably many proves is indistinguishable from zero on . The same argument in fact works for every under the stated pathwise boundedness assumption.
The usual quadratic variation convention includes . If are two continuous finite-variation processes with such that and are continuous local martingales, then is a continuous local martingale of finite variation. It must be constant, and its initial value is zero, so up to indistinguishability of stochastic processes.
Here is a proof of the fact used. Subtract the initial value of a continuous local martingale of finite variation, and stop so that both and its total-variation process are bounded by deterministic constants. The stopped local martingale is a bounded true martingale, so orthogonality of its increments gives, on any deterministic partition of an interval of ,Continuity and the dominated convergence theorem justify the last limit. Remove stopping and use continuity on a countable dense set of times to conclude .
As literally printed, uniqueness is false without normalization. If works then also works for any deterministic constant , since subtracting a constant preserves the local martingale property; this is a genuine omitted convention.
With normalization, existence always holds for a continuous local martingale. Its quadratic variation , obtained as the limit in probability of squared increments, is continuous, increasing, starts at zero and satisfies is a continuous local martingale, so taking supplies the required finite-variation process.
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