The inverse metric condition is
Keeping only terms linear in the metric perturbation gives
Thus the linearized inverse metric is
where indices on are raised with the Minkowski metric.
In the Levi-Civita connection, the background metric is constant and replacing by its correction would multiply a derivative of and produce an term. Hence the linearized Levi-Civita connection is
The products of two connection coefficients in the Riemann curvature tensor are also quadratic and may be discarded. Lowering its first index with gives
Because the coordinate change is , the perturbation changes at linear order by
Substitution into produces terms containing three partial derivatives of . Since partial derivatives commute, every term cancels another with the opposite sign. Therefore
This is the gauge invariance of the linearized Riemann tensor.
All time components of the perturbation vanish. For this immediately gives
For a spatial index ,
by the stated property. Thus the perturbation is transverse.
Its Minkowski trace is purely spatial:
Adding the displayed components and collecting the coefficients of the independent functions , , and makes each coefficient vanish separately, so
Together with and , this proves that the wave is in transverse-traceless gauge.
On the positive axis, and . Taking this limit in the spatial components gives
with evaluated at retarded time . A wave propagating toward the observer along the direction has polarization matrix
Consequently the observed gravitational wave polarization amplitudes are
The mode and the orthogonal combination of do not contribute on this symmetry axis. The observer therefore sees a purely plus-polarized wave; a rotation of the transverse axes would represent the same physical polarization as the corresponding spin-two mixture of plus and cross.

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