Use cylindrical coordinates . The right circular cone is described by and , and the divergence of is . Direct integration gives
To check the boundary flux integral independently, first consider the base . Its outward unit normal vector is , but there, so its flux is zero. Parametrize the lateral surface byThe cross productpoints outward: its horizontal component points away from the axis of the cone. This gives the vector surface element without separately normalizing it. Consequently the lateral flux integral isAdding the zero base contribution agrees with the volume integral, verifying the divergence theorem. The apex has zero surface area; the vector field is smooth there, so no additional flux is hidden at that point.
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