Let and . Their cross partial derivatives agree: . More directly, construct the scalar functionThis exhibits the expression as an exact differential. Along a solution of the differential equation,Thus the general solution isFor , the graph also extends smoothly through and satisfies the original, undivided equation there. Nonzero cannot extend through zero as a finite-valued differentiable solution. The extra vertical component of the implicit zero-level equation is not a graph on an interval and is not an additional solution of this ordinary differential equation.
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