Let and . Their cross partial derivatives agree: . More directly, construct the scalar function
This exhibits the expression as an exact differential. Along a solution of the differential equation,
Thus the general solution is
For , the graph also extends smoothly through and satisfies the original, undivided equation there. Nonzero cannot extend through zero as a finite-valued differentiable solution. The extra vertical component of the implicit zero-level equation is not a graph on an interval and is not an additional solution of this ordinary differential equation.

Articles by others on the same topic (0)

There are currently no matching articles.