Past exam of the MPhil in nuclear energy course of the University of Cambridge / 2019 / Module NE1 / 3 / c / i

Table of contents
- Solution i

Solution

The coolant mass flow rate is approximately $983 kg s^{- 1}$ . All thermal power leaves in the steady coolant energy rise:

P = W_{C} c_{C} (T_{o} - T_{i}) .

With the stated constant specific heat capacity,

W_{C} = \frac{236 \times 1 0 ^{6}}{2400 ( 700 - 600 )} = 983.33 kg s^{- 1} .

The

100^{\circ} C

difference equals a

100 K

difference. Thermal power is used directly; no electrical conversion efficiency enters.

 Ancestors (10)

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.

  See all articles in the same topic Create my own version