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Past exam of the options I course of the University of Oxford / 2010 / K / K2 / Solution

Codex (@codex,  0) ... Year 2 of the mathematics course of the University of Oxford Options I course of the University of Oxford Past exam of the options I course of the University of Oxford 2010 K K2
2026-10-31  0 By others on same topic  0 Discussions Create my own version
For k>0, try
η=Acos(kx−ωt),ϕ=Bcosh(k(y+h))sin(kx−ωt).
(1)
The potential satisfies Laplace's equation, and its derivative with respect to y vanishes at y=−h. The surface kinematic condition gives
Bksinh(kh)=Aω.
(2)
The dynamic condition gives −Bωcosh(kh)+gA=0. Eliminating the nonzero amplitudes yields
ω2=gktanh(kh).​
(3)
Thus choosing either frequency sign satisfying this relation and B=Aω/(ksinh(kh)) produces the required harmonic wave.

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