Past exam of the particle physics course of the University of Oxford / 2018 / 5 / c / Solution

For binary strip readout, report the centre of the hit strip. With uniform impact position across pitch $w$, the position error is uniformly distributed on $[-w/2,w/2]$, soThis assumes no analogue charge sharing between strips.

The magnetic force is $d\mathbf{p}/dt=q\mathbf{v}\times \mathbf{B}$. Since relativistic momentum is parallel to velocity, $d(p^2)/dt=2\mathbf{p}\cdot q(\mathbf{v}\times \mathbf{B})=0$. A uniform transverse field therefore changes momentum direction but not magnitude. If the trajectory turns at angular speed $v/R$, then $|d\mathbf{p}/dt|=p_{T}v/R$. Equating force magnitudes yieldsThis is the positive radius. The sign of $q$ determines the direction of curvature; the source's signed formula can describe an oriented radius. In practical tracking units,