Treat Earth as a stationary spherical source, with , and neglect drag and other bodies. The conserved quantities are total mechanical energy and the angular momentum vector, implying a fixed orbital plane and constant areal velocity. The Kepler problem additionally conserves the Laplace-Runge-Lenz vector. The orbiting object's linear momentum is not constant because gravity exerts a force.
For a circular orbit, , so . Hence
At the closest approach of a noncircular orbit, the velocity is tangential and . Its energy and specific angular momentum are
The pericentre-speed qualification of Kepler orbit classes requires when is genuinely the closest approach. For an ellipse, conservation of h gives . Equating energies at the two turning points and writing gives
The distinct apocentre root is therefore
For an unbound orbit, decreases toward infinity. The asymptotic minimum speed of an unbound Kepler orbit is
It is the limiting infimum, reached only asymptotically: positive for a hyperbola and zero for a parabola. The turning-point interpretation of is essential; if , the same instantaneous energy describes a bound orbit whose is the apocentre instead. [ref]
The orbit is circular for . The speed equals and radial acceleration balances the changing direction of the velocity.
A noncircular ellipse with at pericentre has . Its energy is negative. Merely specifying would make the stated closest-approach point an apocentre, so it is excluded by the geometry; the circular case is listed separately.
The orbit is unbound for : parabolic at equality and hyperbolic above it. The pericentre speed has reached or exceeded the local escape velocity.

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