Past exam of the physics course of the year 1 of the natural sciences course of the University of Cambridge / 2024 / Paper 1 / Section B / 6 / d

The required constant deceleration follows from $v^2=u^2+2as$:Both gravity and sliding friction oppose ascent, so $g(\sin \theta +0.1\cos \theta )=5.76$. WriteThe physical incline solution is $\theta =30.0^{\circ }$ more precisely $30.0389^{\circ }$. The combined mass cancels from the equation. The top of the track is consequently $H=2\sin \theta =1.00117\mathrm{m}$ above its base.