The quoted proton energies are explicitly kinetic. For mean ring radius Rˉ=215 m,Using these expressions rather than setting β=1 at injection givesThe frequency approaches c/C as energy increases; it is the velocity increase, not a change in the prescribed mean ring circumference, that produces the frequency sweep.
C=2πRˉ,γ=1+0.9383GeVK,β=1−γ−2,frev=Cβc.
frev(4GeV)≃217.880kHz,frev(20GeV)≃221.700kHz,frev(50GeV)≃221.885kHz.
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