Choose the principal logarithm, so L(z)=Log(1−z) has branch cut [1,∞). Near zero its Taylor series givesThus zero is a simple pole of residue one, and one is a logarithmic branch point. The function is holomorphic on C∖({0}∪[1,∞)) with this branch. Infinity is also a branch point in the extended-plane description; the function's decay there along the cut plane does not make it a single-valued holomorphic function through infinity.
L(z)=−z−2z2−3z3+O(z4),z3L(z)2=z1+1+O(z).
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