Past exam of the short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford / 2016 / S26 / 1 / 2 / Solution

The color excess is $E(B-V)=0.3-0.2=0.10$ mag, hence $A_V=0.31$ mag. The observed modulus $V-M_V$ is 15.4, while the extinction-corrected modulus is $\boxed{{\mu }_0=15.09}$. Thus $\boxed{d=10^{({\mu }_0+5)/5}\simeq 1.04\times 10^4\mathrm{pc}}$. Distinguishing the apparent and true moduli avoids treating extinction as extra distance.