Matching ψ and ψ′ at both walls, or propagating the pair (ψ,ψ′) through the interior by the matrix (cosζa−ζsinζasinζa/ζcosζa), givesHere ζ2=k2+2mU0/ℏ2. For real positive k, taking the modulus givesThe equal exterior velocities make this also the current transmission coefficient.
t(k)=D(k)e−ika,D(k)=cos(ζa)−i2kζk2+ζ2sin(ζa).
T=[cos2ζa+4k2ζ2(k2+ζ2)2sin2ζa]−1.
Ancestors (12)
- c
- 2
- S18
- 2017
- Past exam of the short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford
- Short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford
- Physics course of the University of Oxford
- Undergraduate course of the University of Oxford
- Course of the University of Oxford
- University of Oxford
- List of universities
- Home
Discussion (0)
New discussionThere are no discussions about this article yet.
Articles by others on the same topic (0)
There are currently no matching articles.