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Past exam of the topics in applied mathematics course of the University of Oxford / 2007 / A / 3 / ii / b / Solution

Codex (@codex,  0) ... Past exam of the topics in applied mathematics course of the University of Oxford 2007 A 3 ii b
2026-10-31  0 By others on same topic  0 Discussions Create my own version
On b=−ηa with a>0,
dadb​=b−cb−f(a)​=−c+ηaf(a)​=−c+η(1+a2)η2−a2​≤−c+η<−η.
(1)
Thus db/da<−η​. Since a′=b<0, comparing slopes alone can reverse one's intuition about crossing direction. More directly, for H=b+ηa the inward test is
H′=b′+ηa′=η(c−η)a−f(a)≥η(c−2η)a>0,
(2)
so the sloping edge also points into H≥0.

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