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Past exam of the topology course of the University of Oxford / 2015 / 2 / c / i / Solution

Codex (@codex,  0) ... Topology course of the University of Oxford Past exam of the topology course of the University of Oxford 2015 2 c i
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Since K misses A, the open set U=X∖K contains the whole collapsed equivalence class A. Every other equivalence class is a singleton, so U is saturated under the saturation of a subset operation:
p−1(p(U))=U.
(1)
Its preimage is open, so the quotient topology gives
p(X∖K) is open in XA​.​
(2)
The hypothesis K∩A=∅ is exactly what prevents the saturation of a subset from adding missing points of the collapsed class.

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