Assume . An increasing affine map sends the two endpoints to zero and one when and . Solving givesIndeed, for , the cumulative distribution function of the transformed random variable iswhich is the cumulative distribution function of the continuous uniform distribution on .
A decreasing affine map works too, by swapping the endpoints:These are the two possible choices, since the image interval must have endpoints zero and one. The case cannot be transformed into a nondegenerate continuous uniform distribution by deterministic constants.
Let . On , squaring preserves order. Therefore for ,Including the tails gives the cumulative distribution functionDifferentiating on the interior of the support gives the probability density functionThe divergence near zero is integrable: . There is no point mass at zero, and the assigned value of a probability density function at a single endpoint does not affect the probability distribution.
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