Let . If , the matrix is zero and the identity is immediate. Otherwise choose the rank factorization from part b. The column space of is the image of .
An idempotent matrix acts as the identity on its image: if , then . Applying this to each column of gives . Substituting yields . Since has full column rank, the represented map is injective, so each column of is zero. Thus .
Now the rectangular cyclic property of the trace givesThis proves that the trace of an idempotent equals its rank using the supplied factorization method. Orthogonality of the projection is unnecessary: the argument applies to every real idempotent matrix.
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