Let . If , the matrix is zero and the identity is immediate. Otherwise choose the rank factorization from part b. The column space of is the image of .
An idempotent matrix acts as the identity on its image: if , then . Applying this to each column of gives . Substituting yields . Since has full column rank, the represented map is injective, so each column of is zero. Thus .
Now the rectangular cyclic property of the trace gives
This proves that the trace of an idempotent equals its rank using the supplied factorization method. Orthogonality of the projection is unnecessary: the argument applies to every real idempotent matrix.

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