Past exam of the year 2 of the earth sciences (geology) course of the University of Oxford / 2024 / Paper 3 / 10 / iii

Table of contents
- Solution iii

Solution

The net reaction quotient is

a_{H_{4} Si O_{4}}^{2}

when the solid and water activities equal one. Therefore its equilibrium line is

x = \frac{1}{2} lo g_{10} K = - 5.515,

a vertical line through the intersection of the other two. There is no dependence on

y

, because the net reaction contains neither hydrogen ions nor sodium ions.

Figure 1.
Stable and metastable mineral boundaries for the common albite-nepheline-corundum equilibrium example
. Original diagram computed from the supplied equilibrium constants. Solid lines show stable coexistence; dashed continuations are metastable. Logarithms are base ten. Details.

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