Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 76 4 a Solution 2026-10-14
Use the explicit printed width law . Its wetted area and hydrostatic pressure integral areAssuming hydrostatic pressure, a horizontal prismatic bed and cross-sectionally uniform velocity, volume conservation and momentum conservation give the prismatic-channel shallow water equationsEquivalently,The coefficient matrix in variables is . Its eigenvalues and the corresponding gravity-wave speed areFor these eigenvalues are distinct and real, establishing strict hyperbolicity in the hyperbolic partial differential equation sense. Since , substitution in the two equations showsFor example . This provides both the slopes and the conserved characteristic quantities. At a dry bed , strict hyperbolicity degenerates and the front is interpreted as the limit from positive depth.
The descriptive word “parabolic” alone would normally suggest and different coefficients. The explicit width in the PDF determines the calculation here; it must not be silently replaced by that other geometry.
Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 83 2 a Solution Created 2026-10-03 Updated 2026-10-14
Interpret as the ambient density: the PDF's phrase assigning it a “depth” is a typographical error. Take , and use a common reference density in inertia while retaining the density difference in buoyancy. This is the Boussinesq approximation, with reduced gravity . For the shallow water approximation, the lower-layer depth must be small compared with longitudinal variation scales, vertical accelerations must be negligible and pressure hydrostatic. The deep ambient is approximated as a hydrostatic pressure reservoir away from the nose; assume a uniform velocity over each lower-layer cross-section and neglect drag and entrainment.
Write the prismatic triangular area as with fixed , so the width at height is . The excess hydrostatic pressure force divided by reference density isThe prismatic-channel shallow water equations are thereforeFor positive depth, divide the first equation by and use it in the second to obtainThe coefficient matrix in variables is . Its two distinct real characteristic speeds areThus the system is strictly hyperbolic for and , though it degenerates at zero depth. Since , direct substitution in the two equations givesHence are the Riemann invariants conserved along their respective characteristic curves. The factor four, rather than the rectangular-channel factor two, comes from the triangular relation .
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 71 3 a Solution Created 2026-10-03 Updated 2026-10-14
Treat the channel as prismatic, with horizontal bottom datum , uniform cross-sectional velocity, and surface height . The area and depth-integrated hydrostatic pressure force divided by density areThe prismatic-channel shallow water equations areSince , they becomeTheir two characteristic speeds are . Using gives the Riemann invariantsThe factor replaces the familiar for a rectangular channel. It comes from the depth-dependent width, not from a different gravitational acceleration.
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 71 3 d Solution Created 2026-10-03 Updated 2026-10-14
Let states and be just left and right of a hydraulic bore moving at speed , and let . Integrating the conservative prismatic-channel shallow water equations across it gives the Rankine-Hugoniot conditionEquivalently the discharge in the shock frame is common on the two sides,Thus, for unequal positive depths,Momentum is conserved through the bore in this ideal model, but mechanical energy is dissipated; an energy-conservation jump must not be imposed as well.
For a stationary bore with rightward flow, , , and the momentum jump must still hold. A compressive hydraulic jump has andThe characteristic curves approach the stationary bore from both sides: upstream flow is supercritical flow, while downstream flow is subcritical flow using the local wave speed . The family travels downstream on both sides. These characteristic directions accompany, rather than replace, the two stationary conservation jumps.