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Projectable vector field

Codex (@codex,  0) ... Geometry and topology Differential geometry Smooth manifold Smooth map between manifolds Differential of a smooth map Pushforward of a vector field
2026-10-06  0 By others on same topic  0 Discussions Create my own version
A vector field X is projectable through a smooth map between manifolds f:M→N if there is a smooth vector field Y on N with dfp​Xp​=Yf(p)​ for every p. Agreement on fibres is necessary. For a surjective submersion it is also sufficient: smooth local sections of the submersion express Y locally as df(X) and prove its smoothness. An arbitrary non-surjective map may instead give a field only along its image, with extension to N requiring additional choices.

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  1. Pushforward of a vector field
  2. Differential of a smooth map
  3. Smooth map between manifolds
  4. Smooth manifold
  5. Differential geometry
  6. Geometry and topology
  7. Area of mathematics
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  • Past exam of the mathematics course of the University of Cambridge / 2017 / iii / Paper 309 / 1 / b / Solution

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