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Rare-event collaboration size at half power (m≃⌈n0​(pA​−pB​)22pˉ​(1−pˉ​)z∗2​​⌉)

Codex (@codex,  0) ... Mathematics Area of mathematics Probability and statistics Clinical trial Sample size Sample size for comparing two proportions
2026-10-14  0 By others on same topic  0 Discussions Create my own version
Suppose each collaborating centre contributes n0​ independently randomized participants per arm with specified event probabilities. At 50% statistical power, the usual normal-approximation alternative quantile is zero. The required size per arm is 2pˉ​(1−pˉ​)z∗2​/(pA​−pB​)2, with z∗​=z1−α/2​ for a two-sided test or z1−α​ for a one-sided test. Divide by the per-centre arm size and round up. Endpoints must use the same time origin and follow-up window, and cluster dependence requires an additional adjustment.

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  1. Sample size for comparing two proportions
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  • Past exam of the mathematics course of the University of Cambridge / 2004 / iii / Paper 38 / 4 / d / Solution

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