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Branch selection by a controlled beam-radius change resolves which of the reciprocal radius ratios is present in a centred Gaussian heterodyne overlap measurement. In reciprocal size-ratio ambiguity in centred Gaussian overlap, the efficiency is $\eta (\rho )=4{\rho }^2/(1+{\rho }^2{)}^2$, with $\rho =w_2/w_1$. Its local signed response isAn infinitesimal increase of the second radius therefore improves overlap when $\rho <1$ and worsens it when $\rho >1$, provided curvature, displacement and polarization stay fixed.

A finite one-sided change needs more care. For a known multiplier $q>1$, direct comparison givesThe threshold is below one because the finite change can overshoot the optimum. In an original example, $\rho =0.99$ is initially on the narrower-beam branch, with efficiency about $0.99990$. Increasing that radius by $10\%$ gives $\rho =1.089$ and efficiency about $0.9928$. The observed decrease alone would misclassify the initial branch if interpreted using the infinitesimal rule.

Use a symmetric beam-radius perturbation for overlap branch selection when two controlled settings are available. Compare $\eta (q\rho )$ with $\eta (\rho /q)$. Since the efficiency is an even, strictly decreasing function of $|\log \rho |$, their difference is positive for $\rho <1$, negative for $\rho >1$, and zero at matching. In the same example with $q=1.10$, the two efficiencies are about $0.9928$ and $0.9890$, correctly selecting the initially narrower beam. The perturbation must be large enough to resolve above measurement noise.

NIST's physical heterodyne setup used beam combination, polarization control and single-mode collection to establish optical matching.^[ref] A practical radius change must preserve those other mode properties; an arbitrary lens adjustment can change wavefront curvature as well and invalidate this one-variable diagnostic.

A symmetric beam-radius perturbation for overlap branch selection compares two controlled settings of one Gaussian beam radius: $q{w}_2$ and $w_2/q$, with known $q>1$. Under the centred, matched-wavefront curvature model of reciprocal size-ratio ambiguity in centred Gaussian overlap, writeThe hyperbolic secant form makes the symmetry explicit: the two settings evaluate the same even function at $u+h$ and $u-h$. Their ordering identifies the sign of $u$, as shown in branch selection by a controlled beam-radius change.

An original extension removes an unknown common scale and recovers the radius ratio itself. Suppose the two measured positive efficiencies satisfyThe factor $A$ is a shared multiplicative nuisance parameter, such as an unchanged response normalization. The symmetric log-overlap ratio eliminates it exactly:For the last equality, use the addition formula for hyperbolic cosine to write the fraction as $(1+t)/(1-t)$, where $t=\tanh u\tanh h$. The defining logarithmic identity for the inverse hyperbolic tangent completes the derivation. Because $h>0$, $D_h$ is positive for the initially narrower beam, negative for the wider beam, and zero at matching.

The inversion of a symmetric Gaussian overlap log-ratio now givesA finite radius ratio exists exactly when $|D_h|<4h$. This condition follows from $|\tanh u|<1$; equality is approached only as one radius ratio tends to zero or infinity. A measured log-ratio outside that interval has no finite solution in this ideal two-setting model.

For an original numerical example, take $q=1.5$, true $\rho =0.8$ and unknown scale $A=0.75$. The ideal readings are $V_{+}=0.7256114$ and $V_{-}=0.5172352$. They give $D_h=0.3385169$, recovering $\rho =0.8$ without supplying $A$ to the inversion. The physical bound is $4h=1.6218604$.

Finite measurement noise still limits branch selection. For small relative errors, the delta method givesA perfectly shared multiplicative fluctuation cancels sample by sample, paralleling common-gain cancellation in heterodyne overlap uncertainty. Independent relative standard uncertainties of $1\%$ in the two readings instead give $u(D_h)\simeq 0.014142$. At the worked point, the derivative of the inverse gives $du/d{D}_h=-0.6780385$, hence about $0.959\%$ relative standard uncertainty in $\rho$. At exact matching the two branches coincide; a noisy sign cannot identify a distinct physical branch there.

These conclusions require $A$ and the other optical mode matching conditions to remain shared across the settings. Changing a lens can alter wavefront curvature and polarization as well as radius. NIST's physical heterodyne apparatus explicitly controlled polarization and spatial matching.^[ref] Larger radius changes may strengthen the log-ratio response while lowering either measured efficiency and changing its noise. Step choice therefore depends on the apparatus and noise model.

Waist-size mismatch in optical heterodyne mode matching reduces interference even when the beam centres coincide. For two circular Gaussian fields with matching polarization and wavefront curvature, define their radius ratio $\rho =w_2/w_1>0$. The centred overlap from Gaussian beam overlap under lateral displacement givesHere $\eta$ is the beat-power fraction relative to a fully matched receiver at the same collected arm powers. Matching total power alone does not set $\rho$.

An original tolerance calculation asks for $\eta \ge 0.90$. Solving the quadratic inequality givesThe allowed ratio is approximately $0.7208$ to $1.3874$. With one radius $100\mu \mathrm{m}$, the other must be about $72.1$–$138.7\mu \mathrm{m}$ in this model. A $140\mu \mathrm{m}$ radius gives only about $89.5\%$ beat power.

The interval has reciprocal endpoints because replacing $\rho$ by $1/\rho$ leaves the overlap unchanged. This reciprocal size-ratio ambiguity in centred Gaussian overlap means the beat magnitude alone cannot tell which beam is wider. Independent beam profiling or a known reference radius resolves that ambiguity.

NIST's heterodyne metrology setup used single-mode fibre and polarization matching to establish a calculable modulation rather than infer matching from collected power alone.^[ref] The radius test above omits displacement, curvature mismatch, clipping and angular misalignment. Radii must be compared at the same receiving plane; equal spot sizes there do not by themselves establish the same full Gaussian optical mode.