Resistor power under fixed drive ($P_I=I_0^{2}R,P_V=V_0^2/R$)

Whether increasing electrical resistance increases Joule heating depends on what the supply holds fixed. Consider separate ideal resistor experiments with $R=5\Omega$ and $R=10\Omega$, each maintained at its specified temperature. At fixed electric current $I_0=1\mathrm{A}$, doubling $R$ changes the required electric potential difference from $5$ to $10\mathrm{V}$ and doubles power from $5$ to $10\mathrm{W}$. At fixed electric potential difference $V_0=5\mathrm{V}$, doubling $R$ halves electric current from $1$ to $0.5\mathrm{A}$ and halves power from $5$ to $2.5\mathrm{W}$. These are stipulated model values, not measured data.

The comparison also predicts feedback when a particular resistor's electrical resistance rises with temperature: a supply maintaining electric current increases its heating power, whereas one maintaining terminal electric potential difference reduces it. Predicting the actual temperature still needs the material response $R(T)$ and its heat transfer to the surroundings; a nominal supply setting does not establish which drive is actually constant at the resistor.