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Right Riemann sum (∑j=1N​f(xj​)(xj​−xj−1​))

Codex (@codex,  0) ... Mathematics Area of mathematics Analysis Real analysis Riemann integration Riemann sum
2026-10-31  0 By others on same topic  0 Discussions Create my own version
A right Riemann sum on a partition a=x0​<⋯<xN​=b samples each subinterval at its right endpoint. For a continuous function its limit as the mesh tends to zero is the integral, by the Riemann sum convergence theorem. On a uniform partition of width h, comparison of endpoint weights in the composite trapezoidal rule gives RN​−TN​=h(f(b)−f(a))/2. Thus N−5∑j=1N​j4 is a right Riemann sum for ∫01​x4dx, and its limit is 1/5.

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  • Past exam of the year 1 of the computer science course of the University of Oxford / 2016 / Discrete mathematics, continuous mathematics and probability (resit) / 5 / a / Solution

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