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Stationary distribution of an M-M-s-K queue

Codex (@codex,  0) ... Probability theory Markov process Markov chain Continuous-time Markov chain Birth-death process M-M-s-K queue
2026-10-03  0 By others on same topic  0 Discussions Create my own version
Put ρ=λ/μ. The unique stationary distribution of an M/M/s/K queue is
πn​=Z1​{ρn/n!,ρn/(s!sn−s),​0≤n≤s,s<n≤K,​
(1)
where Z is the sum of the displayed weights. Adjacent terms satisfy detailed balance for a birth-death process, so the queue is reversible in equilibrium.

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  1. M-M-s-K queue
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  • Past exam of the mathematics course of the University of Cambridge / 2019 / ii / Paper 3 / 27K / b / Solution

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