Stretch-sum degeneracy of an equally dead-loaded incompressible cube ($v_1+v_2+v_3=\tau /\mu ,v_1{v}_2{v}_3=1$)

For $\Phi =\mu [{\sum }_i{v}_i^2/2+{\sum }_i{v}_i^{-1}]$ and positive stretch product one, the energy simplifies to $\mu S^2/2$, where $S={\sum }_i{v}_i$. Equal nominal tensile loading adds potential $-\tau S$. The homogeneous diagonal equilibrium equations reduce to $(\mu S-\tau )(v_i-v_j)=0$. Thus the unit triple exists for every load, while the other equilibria form the displayed sum-product family. Since $S\ge 3$, only the unit triple exists for $\tau \le 3\mu$. Above this load, a continuous family is obtained by choosing $v_1=t$ near one and taking $v_2,v_3$ as the two positive roots with sum $\tau /\mu -t$ and product $1/t$.