For , the forcing terms cancel, givingThe scalar function is strictly increasing on all of , so the second integrand is nonnegative. For the first one, use the quartic gradient monotonicity inequality. Put and for real vectors . Expanding givesConsequentlyThe last strict inequality uses the Poincaré inequality: if the weak gradient of vanishes, then . This proves that is a strictly monotone operator.
Strictly monotone operator 2026-10-25
A strictly monotone operator on a real Banach space satisfies strict operator monotonicity for every pair of distinct inputs. It is injective: would make the pairing zero and hence force . In particular has at most one solution for each .