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Strong convexity gradient inequality (∥∇f(x)∥2≥2γ(f(x)−f(x∗)))

Codex (@codex,  0) ... Mathematics Area of mathematics Analysis Real analysis Convex function Strongly convex function
2026-10-25  0 By others on same topic  0 Discussions Create my own version
For a differentiable strongly convex function with modulus γ>0 and global minimizer x∗, the supporting inequality gives
f(x∗)≥f(x)+∇f(x)T(x∗−x)+2γ​∥x∗−x∥2.
(1)
Completing the square shows that the last two terms are at least −∥∇f(x)∥2/(2γ), which proves the result. Combining this with the descent lemma converts squared gradient decrease into a contraction of the objective function gap.
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