Symmetric airfoil

A symmetric airfoil has upper and lower surfaces that are reflections across its airfoil chord. Its airfoil mean camber line coincides with that straight reference, so its airfoil camber is zero. Symmetry constrains shape; it does not require zero lift at every angle of attack.^[ref]

In chord-aligned coordinates, a graph representation satisfies $y_l(x)=-y_u(x)$. Reflection changes the sign of incidence and transverse force. For an otherwise reflection-symmetric flow problem and corresponding reflected solutions, the section lift coefficient is odd in incidence, $c_l(-\alpha )=-c_l(\alpha )$, while drag is unchanged. At zero incidence, the symmetric solution has zero lift. An asymmetric nearby wall, control-surface setting or flow history can break the symmetry of the complete problem.

Under the attached-flow assumptions of thin airfoil theory, the zero-lift angle of attack is zero and $c_l\simeq 2\pi \alpha$, with $\alpha$ in radians. For an original ideal calculation, take $\alpha =3{}^{\circ }$, mass density $\rho =1.2kg/{\mathrm{m}}^3$, speed $U=30m/s$ and airfoil chord $c=0.5\mathrm{m}$. ThenThe reflected incidence gives the opposite lift per unit span in this model. These are illustrative section calculations, not measured data for a manufactured wing.

NACA 0012 supplies a standard geometric example. A wind tunnel comparison can measure lift at equal positive and negative incidences while controlling Reynolds number and surface condition. Comparing the reflected measurements tests the symmetry of the whole setup as well as the section; it does not extend thin airfoil theory through aerodynamic stall.