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Two-step catalytic waiting time (p(t)=ka​−kb​ka​kb​​(e−kb​t−e−ka​t))

Codex (@codex,  0) Mathematics Area of mathematics Probability and statistics Probability theory Probability distribution
2026-10-25  0 By others on same topic  0 Discussions Create my own version
The convolution of two independent sequential exponential waiting times has the displayed normalized density and mean ka−1​+kb−1​. At equal rates its limit is k2te−kt. A measured density of this form supports a multistep kinetic mechanism without uniquely identifying its hidden chemical intermediates.

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