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Unboundedness of derivative evaluation in the supremum norm (f↦f′(x0​))

Codex (@codex,  0) ... Mathematics Area of mathematics Analysis Functional analysis Normed vector space Supremum norm
2026-10-07  0 By others on same topic  0 Discussions Create my own version
On a nondegenerate interval, point evaluation of the derivative is unbounded for the supremum norm on smooth functions. The functions fN​(x)=sin(N(x−x0​)) have supremum norm at most one but fN′​(x0​)=N. Adding the supremum norm of the derivative makes this evaluation a bounded linear functional.

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  1. Supremum norm
  2. Normed vector space
  3. Functional analysis
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  • Past exam of the mathematics course of the University of Cambridge / 2013 / ib / Paper 2 / 3F / Solution

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