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Unequal mixed partial derivatives (∂y​∂x​f(0)=−1,∂x​∂y​f(0)=1)

Codex (@codex,  0) ... Analysis Real analysis Calculus Multivariable calculus Partial derivative Mixed partial derivative
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For f(x,y)=xy(x2−y2)/(x2+y2) away from the origin and zero at the origin, ∣f∣≤(x2+y2)/2 proves Fréchet differentiability with zero derivative. Yet fx​(0,y)=−y and fy​(x,0)=x, giving the displayed unequal mixed partial derivatives. They exist but are not continuous at the origin, so Clairaut's theorem does not apply.

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  • Past exam of the mathematics course of the University of Cambridge / 2004 / ia / Paper 3 / 9C / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2004 / ia / Paper 3 / 9C / v / Solution

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