In the free-slip Stokes flow temperature model, let the critical temperature be and vertical velocity , . A forced positive second harmonic couples to the negative critical harmonic. Its temperature solvability condition has integrandThe identity follows by substituting and differentiating. Its integral is zero because vanishes on both plates, regardless of the forced boundary value of . Thus the first resonant forcing coefficient vanishes. A generic nonzero conjugate-amplitude term cannot be inferred from wave-number matching alone.
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