 Gauss-Seidel convergence from diagonal dominance and positive definiteness

A strictly diagonally dominant matrix or a real symmetric positive-definite matrix guarantees convergence of the Gauss-Seidel method from every initial vector. These are sufficient conditions.^[ref]

For strict diagonal dominance, putInduct through a sweep. Old coordinates have absolute error at most $E$; previously updated coordinates have absolute error at most $qE\le E$. The component update and the triangle inequality therefore bound the new error by $qE$. This proves $\Vert e^{(k+1)}{\Vert }_{\infty }\le q\Vert e^{(k)}{\Vert }_{\infty }$, a maximum norm contraction.

For a symmetric positive-definite matrix, write $A=D+L+L^T$. The Householder-John theorem applies to $M=D+L$ and $N=-L^T$, because $M^T+N=D$ is a positive-definite matrix. Hence the iteration matrix has spectral radius less than one, which gives the convergence criterion for a stationary iteration.

There is also a geometric reason fresh updates help: the Gauss-Seidel method is exact coordinate descent on the convex quadratic functionHolding the other coordinates fixed, minimizing in coordinate $i$ gives the corresponding row update. A change ${\delta }_i$ lowers $F$ by exactly $a_{ii}{\delta }_i^2/2$. Each fresh coordinate is therefore the minimizer for the current vector, and a complete sweep lowers the quadratic form error unless every coordinate already solves its row. This explains the method's beauty without implying monotone decrease in every vector norm.