A feasible point gives an upper bound on a minimization problem's best value; a suitable Lagrange multiplier gives a lower bound. Lagrangian duality searches for the strongest bound obtainable this way. Matching bounds certify a global minimum.
Let be a nonempty decision domain on which the objective function and the constraint functions are finite. Write the primal problem and its optimization Lagrangian asThe inequality Lagrange multipliers obey ; the equality Lagrange multipliers are unrestricted real numbers. Define the Lagrange dual function and dual optimal value byThe inner infimum keeps , but releases the displayed optimization constraints. It can be , giving an uninformative lower bound. A different domain changes the bound.[ref]
Convex Optimization by Stephen Boyd and Lieven Vandenberghe. §§5.1.1–5.1.3, printed pp. 215–216: domain, Lagrangian, dual function and lower bounds
Here is the entire weak duality argument. For any feasible point and allowable Lagrange multipliers,The first inequality is the definition of an infimum; the second uses and . Taking the infimum over feasible , then the supremum over allowable Lagrange multipliers, gives . No convexity is used.
The Lagrange dual function is a concave function, since each fixed decision makes an affine function of the Lagrange multipliers.[ref]
Convex Optimization by Stephen Boyd and Lieven Vandenberghe. §5.1.2, printed p. 216: pointwise infimum of affine functions
Explicitly, write and choose two points where is finite. For and every ,Taking the infimum over proves the defining concavity inequality. Thus even a difficult primal problem supplies a dual with useful geometry, although evaluating can itself be difficult.For finite optimal values, strong duality means , or zero duality gap. It need not imply dual attainment. For convex optimization, Slater's condition is a sufficient constraint qualification for both when is finite.[ref]
Convex Optimization by Stephen Boyd and Lieven Vandenberghe. §§5.2.2–5.2.3, printed pp. 225–227: gap, strong duality and Slater dual attainment
The Strong Lagrangian property requires an actual finite Lagrange multiplier achieving equality. Convex perturbation duality interprets such a bound as a supporting slope of the perturbed value function. New to topics? Read the docs here!