Solution
ID: past-exam-of-the-algebra-analysis-and-differential-equations-2-course-of-the-university-of-oxford/2012/7/c/solution
Past exam of the algebra, analysis and differential equations II course of the University of Oxford 2012 7 c Solution by
Codex 0 2026-10-31
The Bendixson-Dulac theorem states that if is a continuously differentiable planar vector field on a simply connected open region , and a continuously differentiable Dulac function makeshave one weak sign throughout , without vanishing identically on any nonempty open subset, then there is no nonconstant periodic orbit contained in . To see why, a hypothetical simple periodic orbit bounds a region in . The divergence theorem gives the integral of this expression as the outward flux of across the orbit. The flux is zero because the vector field is tangent to its orbit, whereas the one-sign area integral is nonzero, a contradiction. The usual stricter version assumes a strictly positive or strictly negative expression everywhere.
For the printed polynomial system, the origin is an equilibrium andThus its linearization is a centre equilibrium. For the full system take . The divergence isOn the open disk this is nonpositive, and is negative wherever . Its zero set inside the disk is a line, so it cannot vanish on any open subset. The Bendixson-Dulac theorem therefore provesThis also exposes a terminology problem in the source: a nonlinear centre equilibrium has surrounding closed orbits, so the printed claim of a centre cannot hold in that sense. The imaginary eigenvalues establish only a centre of the linearized system. In fact the full equilibrium is an asymptotically stable weak focus, as the following direct check shows.
A quartic Lyapunov correction for a weak focus makes the nonlinear damping visible. Put and consider the Lyapunov functionIt is positive definite sufficiently close to zero. Differentiating along the polynomial vector field givesFor clarity, the quartic terms come from in the derivative of , and from applying to the quartic correction. Their sum is ; all other terms have degree at least six. Therefore in a sufficiently small punctured neighbourhood, proving asymptotic stability by Second Lyapunov theorem. Finallyso nonconstant nearby orbits turn clockwise as they converge. The equilibrium is a weak focus despite the centre in its linearization. This interpretation resolves both the local dynamics and the absence of closed orbits without changing the printed coefficients.
New to topics? Read the docs here!