Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2003/iii/paper-59/1/b/solution
Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 59 1 b Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
Use local coordinates , at . The Jacobian matrix, its trace and its determinant areConsequently is attracting when , repelling when , and a saddle equilibrium when . A transition between a node and a focus at changes the linear geometry but is not a bifurcation of the local topological phase portrait.
The stationary bifurcation curve is . To identify it, write , . At a non-equatorial equilibrium point, eliminating givesNear , if , these yield and . The two branches are related by the local reflection . Their determinants are , so they are saddle equilibria. This is a pitchfork bifurcation; on the portion with the saddle branches lie on the side where is stable, giving a subcritical pitchfork bifurcation.
A Hopf bifurcation requires , henceThe oscillation frequency is . At the intersection , but : there is a double zero eigenvalue with one eigenvector. The map from to has nonzero Jacobian determinant, so two independent parameter conditions produce this codimension-two bifurcation. Reflection removes quadratic terms; the appropriate initial comparison is with a reflection-symmetric cubic double-zero normal form, subject to the cubic degeneracy checked below.
For completeness, the printed vector field has a subcritical, rather than supercritical, Hopf bifurcation. In the mechanical coordinates , , at its cubic acceleration has coefficient and coefficient . For a small harmonic oscillation, the averaged cubic change of is , whereThus a small unstable periodic orbit lies on the attracting side of the Hopf bifurcation. This calculation matters when comparing the original equations with the later assumed normal form.
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