Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2015/iii/paper-58/3/b/solution

The stellar adiabatic exponents are fixed-composition, constant-specific entropy derivatives:
The chain rule gives . Define the pressure derivatives and . The first law of thermodynamics, with , gives
Combining this with on an adiabat gives
Thus the specific-heat ratio is not generally equal to the three stellar adiabatic exponents.
For the mixture, and . The specific heat capacity at constant volume, obtained by differentiating at fixed mass density, is
Therefore the adiabatic exponents of a monatomic gas-radiation mixture and its specific-heat ratio are
If a relation involving only the exponents is wanted, eliminate from :
For a pure monatomic perfect gas, and . For any calorically perfect gas with constant heat capacities, the same equality holds with its own . In a genuine gas-radiation mixture, , while the exponents are given separately above.
In the radiation limit, and the adiabatic temperature gradient is . This follows independently from photon entropy: a comoving volume has , so an adiabat obeys and . However, is singular in the pure-radiation limit, not . This is the pure-radiation constant-pressure heat-capacity singularity. The equation fixes temperature whenever pressure is fixed, so an ordinary constant-pressure temperature derivative is not available; along the mixture limit and . For photons alone, mass-specific quantities additionally require a material mass label. The often quoted radiation index is its pressure-density adiabatic exponent, not a finite constant-pressure/constant-volume heat-capacity ratio.

New to topics? Read the docs here!