Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 4 1 Solution Created 2026-10-03 Updated 2026-10-14
Let be a finite affine open cover of the projective scheme . For a coherent sheaf , form the Čech cochain complexThe two ways to omit any pair of indices have opposite signs, giving . Its cohomology groups areA projective scheme over a field is a separated scheme. Finite intersections of its affine opens are affine, and a coherent sheaf is quasi-coherent. Higher sheaf cohomology of a quasi-coherent sheaf on an affine scheme vanishes. Thus this is an acyclic cover and the acyclic cover theorem identifies the displayed Čech cohomology with . In particular its degree-zero kernel glues compatible local sections to . A cover by opens also gives vanishing for .
For the cohomology of twists on projective space, take with the usual grading and . On an intersection indexed by the nonempty set ,This follows directly from the construction of the twisting sheaf on projective space: sections of the twist are the degree- homogeneous fractions in the corresponding localization. The Čech differential preserves each Laurent monomial , where and . Such a monomial appears precisely in summands withThe complex therefore decomposes as the direct sum of finite-dimensional cochain complexes indexed by these exponent vectors. Their differentials have only the alternating signs of the simplex incidence maps.
If , this is the ordinary unaugmented simplex cochain complex: its degree-zero kernel consists of the common value on every vertex and has dimension one, while all higher cohomology vanishes. If , choose . A cochain homotopy inserting into the ordered index list, with the sign of that insertion, contracts this subcomplex. Insertion or deletion of preserves the condition ; in , terms inserting and deleting different vertices cancel in pairs, while the term inserting then deleting is the identity. Thus this entire monomial subcomplex is acyclic. Finally, if all , the monomial occurs only in the full intersection, in degree , and contributes one copy of there.
For , these three cases give the complete answer:In the first case counting nonnegative exponent vectors gives . In the top case write with ; then , givingThis is the Laurent-monomial description of top cohomology on projective space. All intermediate degrees vanish for every twist, and the top degree vanishes when . If , then and every twist is trivial, so for every integer , with all higher groups zero.
Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 17 1 Solution Created 2026-10-03 Updated 2026-10-14
Work in the classical setting of varieties over an algebraically closed field . A prevariety is separated when its diagonal morphism is a closed immersion; for prevarieties the diagonal is already an immersion, so this is equivalent to its image being closed. A complete variety has the following closed-projection property: for every variety , projection maps closed subsets to closed subsets. This is universal closedness; since a variety is separated and of finite type, it is equivalent to the structural map being proper.
First consider projective space. In two sets of homogeneous coordinates its diagonal is defined byThese equations hold exactly when the two nonzero coordinate vectors are proportional. They are homogeneous in each coordinate set, so they define a closed subset of . On a common affine chart, the diagonal map is the usual closed immersion defined by equality of the affine coordinates. Thus projective space is separated. If is a projective embedding, its diagonal is the intersection of that closed diagonal with . Consequently every projective variety is separated.
Here is an algebraic proof of completeness, rather than an appeal to projective compactness in an analytic topology. It suffices to prove closedness of projection from projective space over an affine chart , with coordinate ring . A closed subset is cut out by a homogeneous ideal . Put and write for its degree- part. Each is a finitely generated -module, because it is a quotient of the free module on the degree- monomials.
Suppose the fibre over is empty. The specialized homogeneous equations then have no nonzero common zero. By the Hilbert Nullstellensatz, some power of each belongs to the specialized ideal. If those powers are , then every monomial of degree belongs to that ideal. HenceThe Nakayama lemma gives . Since is finitely generated, there is with : choose generators and multiply finitely many elements annihilating their localizations. On the principal open subset , all graded pieces of degree at least vanish too, since the quotient is generated in degree one. Every fibre over is therefore empty: a projective point would have a nonzero coordinate whose degree- power could not vanish. Thus the complement of the projection of is open, proving the required closed-projection property.
An affine open cover of an arbitrary establishes the same result there. Finally, a closed subset of is closed in when is a projective variety, so its image is closed by the preceding argument. ThereforeOver a non-algebraically-closed field, the corresponding statement concerns schemes or geometric points. Projection of rational points alone need not be closed, so it must not replace the completeness definition.
Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 89 5 Solution Created 2026-10-03 Updated 2026-10-14
Choose an ordered affine open cover of the separated scheme. For a quasi-coherent sheaf , the Čech cochain groups and differential areTerms corresponding to empty intersections are zero. Restriction commutes with restriction, so the terms in cancel in pairs. DefineHere an affine cover computes the Čech groups independently of the chosen affine cover. The reason is that finite intersections of affine opens in a separated scheme are affine: the intersection of two is the inverse image of the closed diagonal inside their affine product. Repeating gives the finite-intersection assertion. Quasi-coherent sheaves have no higher cohomology on these intersections. Apply an injective resolution of the sheaf and form the double complex of its Čech cochains. In one direction the higher cohomology vanishes on every affine intersection, leaving precisely the displayed Čech complex. In the other direction the augmented Čech complex of the flasque resolution terms is exact, leaving the global-section resolution computing sheaf cohomology. Thus the two cohomologies agree, and refinement maps between affine-cover complexes induce the same groups. No such affine-intersection claim is being made for arbitrary nonseparated schemes.
For an exact sequence of quasi-coherent sheaves, sections on an affine intersection give an exact sequence of modules, including surjectivity: this follows from the equivalence between quasi-coherent sheaves and modules on an affine scheme. Taking products yields a short exact sequence of Čech cochain complexes. To describe the connecting map, lift a degree- cocycle in to a cochain in . Its differential maps to zero in and therefore is a cocycle in . Changing the lift adds a coboundary there; changing the original representative does the same. This defines the connecting homomorphism. The same lift-and-differentiate argument shows that a class is in its kernel exactly when it lifts to a cocycle in the middle complex, and verifies exactness at the other terms. Thus the resulting sequence isThe sequence must be in quasi-coherent sheaves for this affine-sections argument; that is the intended category here.
For the punctured affine plane, use and . Their rings are and , and the intersection ring is . The two-open Čech complex isConsequentlyThe denominator contains precisely the span of Laurent monomials for which at least one exponent is nonnegative. Every Laurent polynomial has a unique monomial expansion, so the remaining monomials are linearly independent in the quotient and span it. Thereforea countably infinite-dimensional vector space. The brackets here denote cohomology classes. This calculates the Čech cohomology of the punctured affine plane, rather than merely observing that some nonzero cohomology exists.
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 16 3 ii Solution Created 2026-10-03 Updated 2026-10-14
Use the local-presentation definition of a quasi-coherent sheaf: locally it admits a presentation by direct sums of copies of the structure sheaf, with no finiteness requirement on the index sets. If is an -module, choose a free module presentation . Exactness of localization of a module gives the corresponding local presentation of . Hence a sheaf which is associated with a module on every affine open subset is a quasi-coherent sheaf.
For the converse, begin with a quasi-coherent sheaf and a local presentation on an affine open subset . The free sheaves have global sections and : a section has locally finite support, and quasi-compactness of makes its support finite globally. Part (i) identifies the presentation map with an -module homomorphism. Exactness of localization then identifies its cokernel sheaf with for the module cokernel . Thus there is an affine open cover on which is associated with modules.
It remains to show this on an arbitrary affine open subset , rather than only the selected cover. Around each point of , choose an affine neighborhood contained in with such a local presentation. Choose a finite cover refining these neighborhoods. On each the restriction is associated with a module. Its restriction to is therefore the corresponding localization, and the same is true after intersecting with . Put . The sheaf gluing axiom giveswhere the arrow is the difference of the two restriction maps. Localization of a module commutes with kernels and finite products. Localizing this formula at therefore gives exactly the gluing formula for , covered by the . Consequentlycompatibly with restriction. These isomorphisms on the principal open subsets identify with . We have proved the global-section localization for quasi-coherent sheaves and, in particular,
Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 16 5 iii Solution Created 2026-10-03 Updated 2026-10-14
Take the affine scheme , its function field , and the constant sheaf with value . By Question 4(ii), is a flasque sheaf. At the two distinct closed rational points and , let be skyscraper sheaves with value : on an open subset , if and is zero otherwise. Both are flasque sheaves.
There is a natural morphism of sheaveswhich sends a constant rational function to the same element in every summand present on the open subset. At , its stalk map is the identity , and at any other point the target stalk is zero. Thus is a surjection of sheaves, although it is not surjective on global sections. Put .
This can even be an example of sheaves of -modules: let regular functions act on each copy of by multiplication after embedding them in . At the closed points this action is multiplication by a rational function, not evaluation at the point. With these actions, is -linear.
The exact sequence , together with flasque acyclicity, givesHence and . In contrast, use the one-member affine open cover . Its alternating Čech cochain complex has no positive-degree terms, so . We have the explicit discrepancyThe sheaf is not a quasi-coherent sheaf, as also follows from its nonzero higher sheaf cohomology on an affine scheme. Thus this example does not contradict the acyclic cover theorem for quasi-coherent sheaves on affine covers.
Quasi-compact scheme 2026-10-14
A scheme is quasi-compact when its underlying topological space is quasi-compact: every open cover has a finite subcover. Since affine open subsets form a base, this is equivalent to possessing a finite affine open cover. Every affine scheme is quasi-compact.