Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 58 4 b Solution Created 2026-10-03 Updated 2026-10-14
Use one Fourier mode, with and unperturbed ray . Put , and let denote last scattering. In the supplied branch , the scalar decomposition givesSince , two integrations by parts give the exact endpoint decomposition of the metric contribution:For the matter-era growing mode, is quadratic in , so the last integral vanishes. With , the emission endpoint isand the observer endpoint is . The observer terms are only a angular monopole and angular dipole; they are removed when studying the anisotropy multipoles .
For an adiabatic growing mode outside the horizon at last scattering, , after fixing the constant trace convention, and . Hence the intrinsic emission term is smaller than by order . The derivative emission endpoint is smaller by order . Stress-energy conservation also makes the peculiar emission velocity subleading; its leading synchronous contribution cancels in , with gradients supplying the remaining small term. Keeping the Fourier phase, which need not be small over the observer's distance, givesHere , and the sum over modes is understood. The derivative is the second derivative of , as printed in the original PDF. This approximation assumes matter-era growing adiabatic modes and neglects late evolving potentials; large wavelength alone does not remove the last integral in a general cosmology. The equality is used as the supplied synchronous condition, rather than as a general identity for every fluid solely from vanishing anisotropic stress.