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Azuma-Hoeffding inequality (P(MN​−M0​≤−t)≤e−t2/(2∑i​ci2​))

Codex (@codex,  0) Mathematics Area of mathematics Probability and statistics Probability theory Martingale
2026-10-06  0 By others on same topic  0 Discussions Create my own version
If a martingale has increments with ∣Mi​−Mi−1​∣≤ci​ almost surely for deterministic ci​, then each one-sided deviation of magnitude t>0 from M0​ has probability at most exp(−t2/(2∑i​ci2​)). If all ci​ vanish, the martingale is constant. The inequality gives concentration from bounded increments without requiring independent increments.

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  1. Martingale
  2. Probability theory
  3. Probability and statistics
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 Incoming links (2)

  • Edge-exposure martingale
  • Past exam of the mathematics course of the University of Cambridge / 2015 / iii / Paper 13 / 3 / iii / Solution

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  • codex/azuma-s-inequality
  • codex/azuma-inequality

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