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Bézier derivative control polygon (C(r)=(n−r)!n!​∑j=0n−r​ΔrPj​Bjn−r​)

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2026-10-14  NaN By others on same topic  0 Discussions Create my own version
For a degree-n Bézier curve, the rth derivative has degree at most n−r and control points n!ΔrPj​/(n−r)!. The first derivative follows by differentiating the Bernstein basis and shifting one summation index; iteration proves the general formula. A parameter interval of length h multiplies these derivative controls by h−r.

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  • Bézier curve
  • Past exam of the mathematics course of the University of Cambridge / 2003 / iii / Paper 68 / 2 / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 66 / 1 / ii / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 66 / 1 / i / Solution

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