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For an optically thin collisionally excited line, the volume emissivity is approximately $j_{ul}=n_{e}n(X^i)q_{lu}(T_e)h{\nu }_{ul}$ below the transition's critical density. The excitation coefficient includes a factor $T_e^{-1/2}\exp [-\Delta E/(k_B{T}_e)]$, so temperature is needed to convert luminosity into an ionic abundance. Density is needed both to assess collisional quenching of a metastable line and to convert an emission measure into a gas mass. For a uniform recombining ion, for example, $M_i=m_i{L}_{\mathrm{line}}/[n_e{\alpha }_{\mathrm{eff}}h\nu ]$. Temperature structure, density clumping, extinction and unobserved ionization stages introduce further corrections.

A useful density doublet has closely spaced upper energies but different spontaneous decay rates and hence different critical densities. Nearly equal excitation energies reduce temperature dependence of the ratio; similar wavelengths reduce differential extinction and relative calibration errors. Metastable upper levels have sufficiently small Einstein coefficients for collisional de-excitation to compete at nebular densities.

Use statistical weights $g_2=6$, $g_3=4$. The source's O II ground-state term has a typographical error: it is $2s^{2}2p^3{}^4{S}_{3/2}^{\mathrm{o}}$, not ${}^2{S}_{3/2}$. A ${}^{2}S$ term has $J=1/2$, so the printed term is internally inconsistent. The tabulated $J$ values, wavelengths and rates can still be used.^[ref]

At high density, collisions establish a Boltzmann distribution between the upper states. Their energy splitting is small compared with $k_B{T}_e$, so $n_2/n_3\simeq g_2/g_3$. If both lines escape without absorption,The exact ratio includes $\exp [-(E_2-E_3)/(k_B{T}_e)]$, an approximately $0.2\%$ correction at $10^4\mathrm{K}$.

At low density, assume excitation from the common ground state and radiative decay back to it dominate, with no substantial collisional transfer between upper states. Statistical equilibrium gives $n_j{A}_{j1}=n_1{n}_e{q}_{1j}$. Detailed balance relates excitation to the supplied de-excitation coefficient, yieldingEach excitation then produces one line photon, so the spontaneous rate cancels:At high density the upper populations are collisionally thermalized and the ratio retains the radiative lifetimes; at low density radiative escape is nearly certain and the ratio is set by the excitation probabilities instead.

At $T_e=10^4\mathrm{K}$, the two de-excitation coefficients are $C_{21}=1.161\times 10^{-14}$ and $C_{31}=1.1825\times 10^{-14}{\mathrm{m}}^3{\mathrm{s}}^{-1}$. ThusThe useful density range lies between and around these scales. In the independent-upper-level approximation,The density sensitivity of a metastable doublet depends on the error measure. The fractional response $|d\ln R/d\ln n_e|$ is maximal atIf absolute ratio errors are constant, maximizing $|dR/d\ln n_e|$ instead gives $n_e=n_{c,2}$. An unspecified experimental noise model therefore does not define a unique sharper optimum than this transition-density range.

For Ne IV, the same calculation gives critical densities $4.23\times 10^{10}$ and $3.93\times 10^{11}{\mathrm{m}}^{-3}$, with fractional sensitivity peaking near $1.29\times 10^{11}{\mathrm{m}}^{-3}$. This is a useful higher-density diagnostic when O II is saturated. However, Ne${}^{3+}$ and O${}^{+}$ need not occupy the same ionization zone, so their inferred densities need not describe the same gas. The ultraviolet Ne IV pair also needs suitable observations and extinction correction. The proposal is useful with these qualifications, not a guaranteed replacement for the density of the O II emitting zone.

In the idealized isolated-carbon chemical atom interpretation, both beams carry approximately $2.68\mathrm{eV}$ per incident particle, close to the ${}^1{S}_0$ threshold. However equal incident energies do not imply equal excitation channels.

A single optical photon cannot strongly excite any of the listed even-parity $2p^2$ energy levels from the even-parity ${}^3{P}_0$ ground state through an electric dipole transition. In particular ${}^3{P}_0\to {}^1{S}_0$ also violates $\Delta S=0$ and the $J=0\leftrightarrow 0$ restriction. The lowest strong opposite-parity excitations lie well above $2.68\mathrm{eV}$. Thus one expects no strong resonant absorption or corresponding strong atomic fluorescence from these ground-state chemical atoms at this optical wavelength; weak higher-order processes and scattering are separate effects.

Incident electrons can undergo inelastic scattering and collisional excitation. Their orbital angular momentum and exchange with bound electrons allow transfers excluded for a single electric dipole photon. The ${}^1{D}_2$ energy level at $1.264\mathrm{eV}$ and the low fine structure excitations are energetically accessible. One therefore expects scattered electrons with discrete energy losses, possible weak forbidden spectral lines, and collisional or surface relaxation. For example ${}^1{D}_2\to {}^3{P}_2$ has wavelength approximately $10^7/(10192-43.4)=985\mathrm{nm}$; spin mixing supplies the weak spin-forbidden radiative channel.

There is a numerical threshold caveat. Literally,Neither quoted beam reaches ${}^1{S}_0$ from the exact ground state if these are taken as exact monoenergetic values. The electron value rounded to two decimal places could represent an actual energy above threshold; if so, ${}^1{S}_0$ is collisionally accessible and its decay to ${}^1{D}_2$ produces the weak electric quadrupole transition at $10^7/11456\simeq 873\mathrm{nm}$, followed by lower-level relaxation. These emissions require populations and sufficiently low collisional quenching of a metastable line.

An actual solid carbon foil has bands, collective excitations and surface losses, so it need not reproduce the isolated-chemical atom spectrum or selection rules. Its optical and electron-induced emission cannot be predicted quantitatively from the five atomic energy levels alone. This is the limitation of the foil wording in the source.