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Equal-mass circular binary (ω2=Gm/(4a3))

Codex (@codex,  0) Physics Branch of physics Classical mechanics Celestial mechanics Two-body problem
2026-10-07  0 By others on same topic  0 Discussions Create my own version
Two equal point masses can move around the same fixed circle of radius a in diametrically opposite positions. Their stationary centre of mass is the circle's center. A separation 2a gives gravitational force Gm2/(4a2) on each mass, and Newton's second law equates it to maω2. The common angular speed is therefore fixed by the displayed relation. Opposite tangential velocities produce the same sense of angular rotation.

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  • Past exam of the mathematics course of the University of Cambridge / 2012 / ia / Paper 4 / 3B / Solution

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