Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 56 3 Solution Created 2026-10-03 Updated 2026-10-14
Write for the partition-of-unity-normalized degree- B-spline, supported on . Assume . First take distinct knots; endpoint repetitions will be interpreted as confluent limits. For fixed parameter , let , and formwhere the brackets denote a divided difference in the knot variable . This representation follows from the defining properties, rather than assuming a derivative recurrence. If , is a degree- polynomial in all its knot arguments and its order- divided difference is zero. If , every truncated-power term is zero. Between knots it is a degree- polynomial with continuous derivatives. Those support and smoothness conditions determine a one-dimensional spline space: there are spans, the continuity conditions leave coefficients, and vanishing through order at both support ends imposes conditions.
The remaining scalar is fixed by the prescribed integral. Put , . Integrating the truncated power first givesThe order- divided difference of this polynomial is its leading coefficient , so the proposed has integral , exactly the specified normalization.
Now differentiate with respect to and apply the final recursion for a divided difference:In terms of normalized lower-degree B-splines, this is the B-spline differentiation formulaA zero denominator corresponds to a collapsed-support basis term and contributes zero. Repeated knots follow by coalescing distinct knots; at knots where the classical derivative is discontinuous, read the formula on each open span or one-sided. The stated maximal interior continuity corresponds to simple interior knots, while the clamped endpoint repetitions do not affect the interior argument.
Let the control-point abscissae be the Greville abscissaeCollect the coefficient of after differentiating:The difference of the two consecutive knot averages telescopes toso every noncollapsed coefficient is one. The lower-degree basis on the endpoint-trimmed knot vector has partition of unity; equivalently the outer lower-degree basis functions on the original vector have collapsed support. Therefore on the parameter interval. With repeated left endpoint knots at , the clamped basis has , all other values zero, and . Thus fixes the constant of integration. Continuity and endpoint limits now giveThis is linear precision at Greville abscissae. It requires neither equal knot spacing nor a restriction on the other control-point coordinates; those determine the remaining coordinates of the parametric curve.