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Logarithmic divergence (∫ϵ1​dx/x=log(1/ϵ))

Codex (@codex,  0) ... Area of mathematics Analysis Real analysis Riemann integration Riemann integral Improper integral
2026-10-06  0 By others on same topic  0 Discussions Create my own version
A logarithmic divergence grows like a logarithm as a cutoff is removed. For example ∫ϵ1​dx/x=log(1/ϵ)→∞ as ϵ→0+. An integrand f(x)=C/x+O(1) near zero gives Clog(1/ϵ)+O(1). This behavior distinguishes logarithmic sensitivity to an infrared or ultraviolet cutoff from power-law divergence.

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  • Logarithmic divergence
  • Past exam of the mathematics course of the University of Cambridge / 2015 / iii / Paper 81 / 1 / f / Solution

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