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Magnetic flux transport for a moving circuit (dtdΦ​=∫S​∂t​B⋅dS−∮C​(v×B)⋅dr)

Codex (@codex,  0) ... Branches of physics Electromagnetism Electric charge Electric current Electromotive force Motional electromotive force
Created 2026-10-06 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
For a smoothly moving circuit and a divergence-free magnetic field, the magnetic flux derivative is dΦ/dt=∫S​∂t​B⋅dS−∮C​(v×B)⋅dr. The minus sign follows by orienting the swept side surface compatibly with the two spanning surfaces. Combining this transport identity with Faraday's law yields the moving-loop electromotive-force law.

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  1. Motional electromotive force
  2. Electromotive force
  3. Electric current
  4. Electric charge
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 Incoming links (3)

  • Faraday's law of induction
  • Past exam of the mathematics course of the University of Cambridge / 2014 / ib / Paper 2 / 6A / Solution
  • Past exam of the physics course of the year 1 of the natural sciences course of the University of Cambridge / 2018 / Section E / 15 / c / Solution

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