Write for the constant isothermal sound speed squared and for the constant Alfvén speed squared. The horizontal magnetic field has no vertical magnetic tension; magnetostatic equilibrium is
Consequently the magnetized isothermal atmosphere has
The sign of specifies the orientation of the magnetic field. The adiabatic sound speed is , also constant.
For the proposed normal mode, let , , and temporarily write for its constant complex amplitude. The divergence amplitude is . Using and , the Eulerian and Lagrangian fluid perturbations give
Since , the magnetohydrodynamic total pressure amplitude is
The vertical derivative of is . For the magnetic tension perturbation, the terms proportional to from and cancel, leaving
Thus the linearization really reduces to the constant-coefficient eigenvalue problem
For a static ideal magnetohydrodynamics equilibrium with conservative gravitational acceleration, the magnetohydrodynamic energy principle gives a Hermitian operator for the restoring force in the mass density weighted inner product, provided the surface terms vanish. The factor removes the exponential mass density weight. This can be checked directly, without assuming stability: set , , and . Then , where
This is a Hermitian matrix for real and real positive . Therefore every squared frequency is real; negative values give exponential growth, rather than an oscillation with a complex squared frequency. In an infinite atmosphere these are generalized plane waves, not finite-total-energy global modes.
At and , the equation, after cancelling its magnetic terms, gives . For nonzero magnetic field, the equation also gives . Substituting and then yields
For a nontrivial mode ; otherwise these equations and force every component to vanish. Substitution in the vertical equation gives
For example, the determinant provides an independent check:
To prove the claimed “if and only if”, rather than merely locating a zero eigenvalue, use the magnetic buoyancy energy criterion
If , every term is nonnegative, so all eigenvalues are nonnegative for every wavevector, including . If , choose , any fixed , and , , . The first two squares vanish; the remaining value is
which is negative for sufficiently small nonzero . The Rayleigh quotient of this displacement is therefore negative, proving a negative eigenvalue and an unstable normal mode. This uses precisely the assumption that boundary conditions do not exclude the chosen wavelengths. Equality is a neutral threshold, not exponential growth.
Finally the plasma beta is . Hence
The magnetic field is assumed nonzero in the marginal-mode elimination and in the finite expression. The positive-sound-speed, nonmagnetic limit remains covered by the energy identity; for the usual it is stable. Parker instability occurs because magnetic pressure supports part of the atmosphere's weight while the gas can drain along gently bent magnetic field lines. The resulting buoyant displacement can release Newtonian gravitational potential energy; choosing long wavelengths along the magnetic field makes the stabilizing magnetic tension small. The completed-square calculation quantifies this competition, including the adiabatic process restoring force.