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Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 37 1 b Solution Created 2026-10-03 Updated 2026-10-07
The regression residual vector is , where is the hat matrix. Both and are symmetric idempotent matrices, and . Therefore and the linear image of a multivariate normal vector givesThis multivariate normal distribution is singular, with rank : fitted-residual orthogonality forces . Specifically, and for distinct observations. Thus regression residuals are generally neither independent nor identically distributed, even though the model errors are. Also and is independent of , which justifies the standard errors and exact Student t-tests below.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 25 1 b Solution Created 2026-10-03 Updated 2026-10-07
For any , the linearity from part (a) givesalmost surely, and the right side has a normal distribution. This is the defining linear-combination criterion for a multivariate normal distribution; singular covariance matrices are allowed.
Passing to the limit in the inner products of the partial sums givesThe passage to the limit is justified by Cauchy-Schwarz inequality and convergence. Equivalently, the vector's characteristic function isThus both joint normality and the complete covariance matrix follow from the Hilbert-space inner product.
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 30 1 c Solution Created 2026-10-03 Updated 2026-10-07
The ordinary least squares estimator is . Consequently the fitted values and regression residuals areAn affine transformation of a multivariate normal distribution is again multivariate normal, possibly with a singular covariance matrix. For a random vector with covariance matrix , its transformed covariance matrix is . Since , and , these results giveBoth multivariate normal distributions are supported on their respective projected subspaces. In particular, has variance and has variance ; the regression residuals need not be mutually independent.